All right, we can they in court later, the notion for circle so I hat for the circle was calculated as the following value. Now that is very important, because that is how you actually solve for the unknown. So, um let me just explain what concurrent forces are on what complainer forces are. That would be the component of force A D. In is the direction as well as the force off this weight acting downwards, which is a 500 newtons. All right, so you will notice if two has no. Merely said, the fundamentals of engineering mechanics by s rajasekaran is universally compatible with any devices to read Users can easily upload custom books and complete e-book production online through automatically generating APK eBooks. So I can't go back to the question and make sure you answered everything. If you have a right angle triangle and you have the 90 degree angle there and then you have your angle V, then this would be your Jason side. So this is if b over here and in the angle opposite it is the 50 degrees said sign 50 degrees equals 888 divided by sine off 90. That means it is somewhere between the we know this distance here is two meters that distance there's two meters on this distance. So just make sure you have all the details off the magnitude of the forces off the distances off the points. So that's why I always quick to use the origin as your reference point. Second would be using your equations of equilibrium, which is some of the forces Equal X equals error in the X equals zero and some of the force in the Y equals era. So that's a why on And, um, it's assumed right is a X. All right, because we are free Body diagram started from zero to this point. In this case, it's a circular disk in an X y Z airplane, and you have forces acting on the disk. It's Newton's. All right, Been at point A. That is the answers we are looking for, and then of course, you can just write them in three significant digits because that's how they want the answers in this module that would be equal to minus 11.9 Killer Newtons. 300 cause 60 I plus 1.2 J. If you would like to redraw this on the beam, So here we have deem. So became click clear again A sea of it here then you go once again shift five for Victor Then we've defined Victor A. So here we have I with Artur line on top. The four forces acting on the post in Cartesian Victor Form determine the magnitude and direction off theatre off Force One. The Fundamentals of Engineering ( FE) exam, also referred to as the Engineer in Training ( EIT) exam, and formerly in some states as the Engineering Intern ( EI) exam, is the first of two examinations that engineers must pass in order to be licensed as a Professional Engineer in the United States. But if you don't show your working art, then they will mark you down. So the some off the moments of our point a must equal zero. But before we do that, I will just briefly show you the different formulas you can use to calculate the moments of inertia over here. That's called co interior angles on. All right, so you look here, so lift is negative. Then at four, it goes to five. All right, So how do you do this? Method of Sections Example: in this video, we will be doing an example where we have to use the method off sections. Victor two points X anywhere along the line off action off. It is for over three pie, and that will give you the distance from the the halfway off the circle to the points off the central aid. Oh, if it's because it's above point. All right, so to get our the position, Victor are we write it in terms of I and J and K, but we just working two dimensions, so it's just I and J. All right, so you'll notice that the answer off the dot product will always be a value or a magnitude . All right, so now what we can do is we can calculates are a all right. Comment. If all right, and we have 110 degrees. So something you'll notice in this module. X points is equal to three. All right. You didn't because the magnitude is bigger. All right, so there we have are one equation. So that is what you're actually looking for. Plus. Mutiny divided by mutant. And then we can assume the full length off the beam because we don't know where we sectioned it. Instead of a tension force. It doesn't necessarily have to be around a point, but just, um, anyway, within your free body diagram. 9. So what you actually going to be doing now is you'll be given a beam and your section it or cut it at a certain point along the beam, and then you would then draw the free body diagram off that cut peace within the being all right or a part off the bean. So you're basically just add all these valued minus three I plus four j plus four I plus two j plus three I minus five j So are highlighted all the eyes and all the jays of in you . And then that would then be K. So you'd have I for X J for y and K for is it all right? 28. 24. This means you will have to pass the FE Exam. All right, so that is equal to, um the moment off. We teach the major component of this course include particle equilibrium, rigid body equilibrium, structural analysis center, roids and inertia as well as internal forces. When you calculate the force parallel to a C. All right, so a c is a force parallel. 19. Mutants must equal zero. All right, that is an equal to this in Isha. Ethics and Business - Engineering economics, Contracts. All right, so, to calculate the century of a triangle, it is the distance off the length of the triangle to the point of the right angle divided by three. All right, so here we have signed city equals sign 31.98 equals 60 and we have minus cause off city equals positive cause 51 point 98 and zero. Why J across minus 60 k So the J and K, you're gonna be left with an eye component. On day we have the distance. And that's all divided by two. Just the thing to note. That will give you an answer off 28 to 7 millimeters square. Plus that square. So that's what we have here. Integrity Statement | 60 I, you could have written on Sign off 30 and cause off city. All right. So if we assume it's an equilateral triangle and that means the high part in use length here, his six meters. So in this case, it's B and B. We have 12345 We have all five forces. You have to use knowledge off Centrowitz to position the forces. We're in this case, it is a wire. All right, so let's do this. Aren't the pages positive into the page is negative? So this angle, they this angle here is equal to deter because off the alternating angles, cause this line that line or parallel All right, so if we choose up as positive and you do the some of the forces in the UAE Sequels era then we have, Which is this Is there Jason side on? When I used to do the subject on, they would give me my calculation mark on the final mark where the people who had just used a calculator will not get marks for calculations. Now, what is a position, Victor? All right, so when we do the example, you'll see exactly what I mean. All right, so if we have a line perpendicular on another line, it is then 90 degrees forms a 90 degree angle, and that's represented by this little square at the corner. So if you continue, you can write out the formula for position Victor, which is XB minus X A. So as you can see because we know if I d has a force, then that means there's an external force acting at this joint. So now we have all the angles on the inside of this triangle. Anti clockwise is positive. All right, it's to the positive X direction. So that means over here we assumed the force of a Y is acting upwards, but in fact, the force of a wise actually acting downwards. So basically, you will get a question. All right, so the distance between verse Force and 20 is zero, so you could ignore this force. See search results for this author. All right, so that's some off 4th 1 plus forced to plus force three, Force One is equal to positive 50 k forced to equal to minus 40 cave because it's acting in the negative direction. So the negative K direction all right on then, forced three is also negative minus 50 k So if you some all that up going to be left with minus 60 K and that's all measured in mutant. So to break it up into its components, we could simply redraw it. All right, so what do you need to know? So if one we have and if to we need to calculate the Cartesian victor if to So what I usually like to do is I like to read draw this plane in two dimensions just that easier to work from. So that's the X. All right, so that's multiplied by full Andi you'll notice as it rotates, would rotated. All right, so, um, if you're negative answer, obviously art means compression and in means tension. All right, cross that cross product, the Cartesian victor off the force, or right, And then your answer will be a Cartesian victor as well. Those are all the forces in the X direction, this force and that force. Um, we will called. You can either calculate the century off the quarter circle on the small arc and then add them together. All right, so then you are left with an angle over here. If you then, um, render a positive answer for force a Force B and four C or right or just a positive on send general for any of your forces on. So that is that length over there, Plus this entire length off the breath off the rectangles. In the next video, we will be, I'm doing an example for equilibrium in two dimensions where you have to know how to apply these difference conditions All right, because it's negative. Why B minus y a zit be mine. All right, so the next video, we will be doing a nice example that will be worth watching. And then this little diagram basically represents what I'm trying to explain in these formulas. All right, sir, looking here, we have forced a B in the Y direction. All right, so here, have a little note. Right. It's just saying the unit Victor divided by F All right, so it's the same thing, not the unit Vector, the Cartesian victor divided by the magnitude of the force that equals the unit vector. So if we are doing some of the forces in the X direction, All right. Andi. All rights. It has to be at the trust joint. So that means we have C B and A B A which are Kaleena running along the same line. Just making sure. If you state for example, it's tension, and then you calculate the value of that force and then you get a negative answer. This one smudged it. I didn't confuse you too much, but, um, we cannot move onto calculating the internal forces. 2.45 rights divided by the magnitude. All right, which we calculated now as eight point 04 All right, then Cosby tha is equal to 1.41 divided by 8.4 and cause gamma is equal to minus 2.83 divided by the magnitude, which is once again 8.4 All right, so we can now plug these into a calculator. So for the rectangle. All right? It's, uh we would then have Krauze 2700 course 20 times, 700. So these two will always be the same. It simply means that that force is actually acting in the opposite direction, so it means it is actually being compressed. I'm not going to go through all of them cause we just don't have time for that. You do it like that. So we'll leave for Force one for loss because it's the most complicated. Number one you know that you have to draw the free body diagram at BNC because B is where the unknown force acts. So no, um very important. The question will ask something like replaced the loading system by an equivalent result in force and specify the X Y and Z coordinates off its line of action. So that's why I like to just stick to opposite the Jasons and high part in use. 10 to the negative three mutants. And this triangle living here, right? That is not Colin. So we have a negative or right. That six meters minus 10 at six meters. Let's start with, if full so, if forced magnitude is equal to 10. Victor gives you the Cartesian victor off the force. Andi, once again, we working with the opposite side. We're right, so there we have our result in force. So you basically need to know how to calculate the area off a rectangle and a triangle, which is length times, breadth. Um, we can't say 12 grand, 12 squared times 10 to actually, we will just leave kilograms kilograms sa units. Delete sign equals, and that is 1.6 five meters. So if you have any two points in space or within the X Y z it plain, All right, so here we have point A and point B, if you want to find the Cartesian vector between there, it's called a position vector. I plus minus six, minus seven or positive. So a exit acting here and then this is a perpendicular distance too pointy. And along here we have a force. We can assume a length off X. Victor's on Victor's along a line. Then they'll mention the points. And then there's a change in force over here by the distributed load. So this is a rectangle. So you know, the same toyed runs along the centre line, all right, between the ark with this angle is equal to offer, and this angle is equal to offer. Meter, 0.5 meters, which is two point five, provided no external forces acting on point. 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